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If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit the ground, calculate the velocity of the watermelon as it hits the ground.

Respuesta :

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

  • Initial velocity of the Watermelon;[tex]u = 0m/s[/tex]
  • Time taken for the Watermelon to hit the ground; [tex]t = 1.5s[/tex]
  • We know that, Acceleration due to gravity; [tex]g = 9.81 m/s^2[/tex]

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

[tex]v = u + at[/tex]

Now, under gravity, acceleration ''a" will Acceleration due to gravity;[tex]g = 9.81m/s^2[/tex], "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.

So, we substitute our values into the equation

[tex]v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s[/tex]

Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s

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