The velocity of the watermelon as it hits the ground is 14.715 m/s.
Given the data in the question;
Since the Watermelon was dropped from rest,
Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.
From the First Equation of Motion:
[tex]v = u + at[/tex]
Now, under gravity, acceleration ''a" will Acceleration due to gravity;[tex]g = 9.81m/s^2[/tex], "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.
So, we substitute our values into the equation
[tex]v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s[/tex]
Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s
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