Respuesta :

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Using Trigonometry :

  • [tex] \tan(y) = \dfrac{20}{21} [/tex]

[tex]\\ \rm\Rrightarrow tan\theta=\dfrac{Perpendicular}{Base}[/tex]

[tex]\\ \rm\Rrightarrow tany=\dfrac{JL}{KL}[/tex]

[tex]\\ \rm\Rrightarrow tany=\dfrac{20}{21}[/tex]