the correct answer is first,fifth,sixth
x² -6x+2=0
a=1 a>0 so it has minimum value/point
since it is quadratic equation, hence the extreme value is at minimum point which is (3,-7)
in order to get that differentiate x²-6x+2
2x-6=0
2x=6
x=3
subtitude x=3 into the original equation
(3)²-6(3)+2
9-18+2
-7
extreme point (3,-7)
in order to know whether it is the solution of the equation or try subtitude it into the equation
(-3+√7)² -6(-3+√7)+2≠0
36-12√7≠0
(-3-√7)² -6(-3-√7)+2≠0
36+12√7≠0
(3+√7)² -6(3+√7)+2=0
(3-√7)² -6(3-√7)+2=0
hence the solutions are 3+√7 and 3-√7
