The time that most of the students get is 1 hour and 25 minutes, computed using fractions and percentages.
Fractions are a relational representation of certain parts of a quantity, to the total parts of that quantity.
Written as a/b, read as "a by b", functions as a divided by b, represents a fraction a over b, where a is the numerator and b is the denominator.
Percentages are a fractional representation of a quantity, where the whole quantity is fixed to be 100.
Fractions are converted to percentages by multiplying them by 100, while percentages are converted to fractions by dividing them by 100.
In the question, we are informed that Roy gets 10% extra time in school exams.
We are asked for the time that is given to most of the students if Roy gets 1 hour 33 minutes and 30 seconds.
For standardization, we work in seconds.
We assume the required time to be x seconds.
Time given to Roy:
30 seconds implies 30 seconds,
33 minutes implies 33*60 = 1980 seconds,
1 hour implies 1*60*60 = 3600 seconds.
Thus, the total time given to Roy = 30 + 1980 + 3600 = 5610 seconds.
We are informed that Roy gets 10% extra time in school exams.
Thus, the time given to Roy = Normal time + 10% of normal time,
or, 5610 = x + 10% of x,
or, 5610 = x + 10/100 of x {percentages are converted to fractions by dividing them by 100},
or, 5610 = x + x/10,
or, 5610 = 11x/10,
or, x = 5610*10/11 = 5100.
Thus, the time given to most of the students = 5100 seconds = 5100/60 minutes = 85 minutes = 1 hour and 25 minutes.
Thus, the time that most of the students get is 1 hour and 25 minutes, computed using fractions and percentages.
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