Using the expected value, it is found that the mean of the distribution equals $0.1.
The probabilities of each outcome are:
Thus, the mean is given by:
[tex]E(Y) = 0.0000001(1000000) + 0.9999999(0) = 0.1[/tex]
Thus showing that the expected value is $0.1.
A similar problem is given at https://brainly.com/question/24855677