The coordinate of the y-intercept of the line whose equation is 12x + 11y = 6 is at (0, 6/11)
The y-intercept of a line is the point where the value of x is zero
Given the equation 12x + 11y = 6
The y-intercept of the line occurs at the point where x = 0. Substitute x = 0 into the equation
12(0) + 11y = 6
0+ 11y = 6
11y = 6
Divide both sides by 11
11y/11 = 6/11
y = 6/11
Hence the coordinate of the y-intercept of the line whose equation is 12x + 11y = 6 is at (0, 6/11)
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