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A car traveling initially at 9.49 m/s accelerates at the rate of 0.988 m/s^2 for 3.05s. What is it’s velocity at the end of the acceleration?

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OverpoweredNoob

Answer:

12.50 m/s

Explanation:

Vi = 9.49 m/s

a = 0.988 m/s²

t = 3.05 s

Vf = ?

Vf = Vi + at

Vf = 9.49 + (0.988)(3.05)

Vf = 12.50 m/s

Answer:

• From first equation of motion:

[tex]{ \boxed{ \bf{v = u + at}}}[/tex]

substitute:

[tex]v = 9.49 + (0.988 \times 3.05) \\ v = 9.49 + 3.0134 \\ v = 12.50 \: \: m {s}^{ - 1} [/tex]

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