A 160cm long string has two adjacent resonance at 85hz frequencies . calculate : 1- the fundamental frequency , 2- the speed of the wave

Respuesta :

Length=l=160cm=1.6m

Frequency=85Hz

#1

Fundamental frequency be v

[tex]\\ \sf\bull\longmapsto v=\dfrac{\nu}{2\ell}[/tex]

[tex]\\ \sf\bull\longmapsto v=\dfrac{85}{2(1.6)}[/tex]

[tex]\\ \sf\bull\longmapsto v=\dfrac{85}{3.2}[/tex]

[tex]\\ \sf\bull\longmapsto v=26.6Hz[/tex]

#2

First we have to find wavelength

[tex]\\ \sf\bull\longmapsto \lambda=\dfrac{c}{v}[/tex]

[tex]\\ \sf\bull\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{26.6}[/tex]

[tex]\\ \sf\bull\longmapsto \lambda=0.112\times 10^8m[/tex]

[tex]\\ \sf\bull\longmapsto \lambda=112\times 10^5m[/tex]

[tex]\\ \sf\bull\longmapsto \lambda=1.12\times 10^6m[/tex]

Now..

Velocity be v

[tex]\\ \sf\bull\longmapsto v=f\lambda[/tex]

  • f is frequency

[tex]\\ \sf\bull\longmapsto v=26.5\times1.12\times 10^6m[/tex]

[tex]\\ \sf\bull\longmapsto v=29.68\times 10^6[/tex]

[tex]\\ \sf\bull\longmapsto v=2.9\times 10^7m/s[/tex]