9514 1404 393
Answer:
(c^3-3c^2d+3cd^2-d^3)/c^18
Step-by-step explanation:
It appears you want to simplify ...
[tex]\left(\dfrac{c^6}{c-d}\right)^{-3}=\left(\dfrac{c-d}{c^6}\right)^3=\boxed{\dfrac{c^3-3c^2d+3cd^2-d^3}{c^{18}}}[/tex]
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The relevant rule for exponents is ...
a^-b = 1/a^b
The coefficients of the expansion of the binomial are found in Pascal's triangle.
