For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.
We can calculate the initial speed to reach 110 cm of height with the following equation:
[tex] v_{f}^{2} = v_{i}^{2} - 2gh [/tex]
Where:
[tex] v_{f}[/tex]: is the final speed = 0 (at the maximum height of 110 cm)
[tex] v_{i}[/tex]: is the initial speed =?
g: is the acceleration due to gravity = 9.81 m/s²
h: is the height = 110 cm = 1.10 m
Hence, the initial velocity is:
[tex] v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s [/tex]
Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.
You can see another example here: https://brainly.com/question/13359681?referrer=searchResults
I hope it helps you!
