The equation of the circle that has its centre at (7, -24) and passes through the origin is (x - 7)² + (y + 24)² = 625.
What is an equation of a circle?
A circle can be characterized by its centre's location and its radius's length.
Let the centre of the considered circle be at (h,k) coordinate and the radius of the circle be 'r' units.
Then, the equation of that circle would be:
(x-h)²+(y-k)²=r²
The equation of a circle is given as (x-h)²+(y-k)²=r², where (h,k) is the coordinate of the centre of the circle, and r is the radius of the circle.
Since the given circle is needed to pass through the origin and the coordinates of the centre of the circle are (7, -24). Therefore, the distance between the origin and (7, -24) will the radius of the circle.
Therefore, the radius of the circle will be,
Radius = √[(7-0)² + (-24 - 0)²]
= √(49 + 576)
= √(625)
= 25
Now, the equation of the circle that is centred at (7, -24) and has a radius of 25 units is,
(x - h)² + (y - k)² = r²
[x - 7]² + [y - (-24)]² = (25)²
(x - 7)² + (y + 24)² = 625
Hence, the equation of the circle that has its centre at (7, -24) and passes through the origin is (x - 7)² + (y + 24)² = 625.
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