a) Her acceleration during the slide is -6.67 m/s².
b) She slides 1.03 seconds until she stops.
a) We can find her acceleration during the slide with Newton's second law:
[tex] F = ma [/tex]
Where:
F: is the force
m: is the mass = 92.45 kg
a: is the acceleration =?
The force acting on the baseball player is equal to the friction force ([tex]F_{\mu}[/tex]), and it is negative because it is in the opposite direction to the motion:
[tex] -\mu N = ma [/tex]
[tex] -\mu mg = ma [/tex]
[tex] a = -\mu g [/tex]
Where:
N: is the normal force = mg
μ: is the coefficient of kinetic firction = 0.68
g: is the acceleration due to gravity = 9.81 m/s²
Hence, her acceleration during the slide is:
[tex] a = -0.68*9.81 m/s^{2} = -6.67 m/s^{2} [/tex]
b) We can calculate how long does she slide until she stops with the following kinematic equation:
[tex] v_{f} = v_{0} + at [/tex]
Where:
[tex] v_{f} [/tex]: is the final speed = 0 (when she stops)
[tex] v_{0} [/tex]: is the initial speed = 6.87 m/s
t: is the time =?
Then, the time is:
[tex] t = -\frac{v_{0}}{a} = -\frac{6.87 m/s}{-6.67 m/s^{2}} = 1.03 s [/tex]
You can learn more about Newton's second law here: https://brainly.com/question/19860811?referrer=searchResults
I hope it helps you!
