These following ordered pairs are on the graph:
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An ordered pair (x, f(x)) will be on the graph if replacing them into the equation, we get an equivalence.
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The equation is:
[tex]f(x) = x^2 - 1[/tex]
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(0,1)
Here, we test [tex]x = 0, f(x) = 1[/tex]
Replacing into the equation:
[tex]1 = 0^2 - 1[/tex]
[tex]1 = -1[/tex]
False, so not on the graph.
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(0,1)
Here, we test [tex]x = 1, f(x) = 0[/tex]
Replacing into the equation:
[tex]0 = 1^2 - 1[/tex]
[tex]0 = 0[/tex]
True, so on the graph.
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(3,5)
Here, we test [tex]x = 3, f(x) = 5[/tex]
Replacing into the equation:
[tex]5 = 3^2 - 1[/tex]
[tex]5 = 8[/tex]
False, so not on the graph.
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(5,24)
Here, we test [tex]x = 5, f(x) = 24[/tex]
Replacing into the equation:
[tex]24 = 5^2 - 1[/tex]
[tex]24 = 24[/tex]
True, so on the graph.
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(-2,3)
Here, we test [tex]x = -2, f(x) = 3[/tex]
Replacing into the equation:
[tex]3 = (-2)^2 - 1[/tex]
[tex]3 = 3[/tex]
True, so on the graph.
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(-4,-17)
Here, we test [tex]x = -4, f(x) = -17[/tex]
Replacing into the equation:
[tex]-17 = (-4)^2 - 1[/tex]
[tex]-17 = 15[/tex]
False, so not on the graph.
A similar question is given at https://brainly.com/question/2102317
