Option 1 - StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.
Step-by-step explanation:
Given : Expression "six less than the quotient of a number and two, increased by ten".
To find : What is the expression and value of expression when n = 8?
Solution :
Let the number be 'n'.
The quotient of a number and two i.e. \frac{n}{2}2n
Six less than the quotient of a number and two i.e. \frac{n}{2}-62n−6
Six less than the quotient of a number and two, increased by ten i.e. \frac{n}{2}-6+102n−6+10
The required expression is \frac{n}{2}-6+102n−6+10 .
Now, when n=8,
\frac{n}{2}-6+10=\frac{8}{2}-6+102n−6+10=28−6+10
\frac{n}{2}-6+10=4-6+102n−6+10=4−6+10
\frac{n}{2}-6+10=82n−6+10=8
The value of the expression is 8.
Therefore, option 1 is correct.
StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.
