The least number of buses required for the trip will be 5 buses.
It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.
First, let us make a note of the information we have. There are 5 ice-creams. 5 ice-creams cost $125.
Step 1: Let’s find the cost of 1 ice cream. In order to do that, divide the total cost of ice-creams by the total number of ice-creams. The cost of 1 ice-cream = Total cost of ice-creams/Total number of ice-creams = 125/5 = 25. Therefore, the cost of 1 ice cream is $25.
Step 2: To find the cost of 3 ice creams, multiply the cost of 1 ice cream by the number of ice-creams. The cost of 3 ice-creams is cost of 1 ice-cream × number of ice-creams = 25 × 3 = $75. Finally, we have the cost of 3 ice-creams i.e. $75.
Total number of classes = 9
Number of students in each class = 25
Number of teachers = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
A total number of students.
= 9 × 25
= 225
A number of chaperones.
= 4 × 2
= 8
Total people = 225 + 8 + 4 = 237
Least number of buses required for trip = Total people / Bus hold
= 237 / 45
= 5.266
Learn more about the unitary method here:
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