Which system of linear inequalities has the point (3, -2) in its solution set?

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MrRoyal MrRoyal · Answer 1 · 2021-07-20T02:46:45+02:00

Answer:

None of the given system of linear inequalities

Step-by-step explanation:

Given

[tex](x,y) =(3,-2)[/tex]

Required

The line inequalities with the above solution

The first set of linear inequalities, we have:

[tex]y < -3[/tex]

[tex]y \ge \frac{2}{3}x - 4[/tex]

[tex]y < -3[/tex] implies that the values of y is -4,-5.....

While [tex](x,y) =(3,-2)[/tex] implies that y = -2

Hence, the first set is wrong

The second set of linear inequalities, we have:

[tex]y > - 2[/tex]

[tex]y \ge \frac{2}{3}x - 4[/tex]

[tex]y > - 2[/tex] implies that the values of y is -1,0.....

While [tex](x,y) =(3,-2)[/tex] implies that y = -2

Hence, the second set is wrong

Martebi Martebi · Answer 2 · 2022-04-12T17:49:32+02:00

The system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4.

A system of linear inequalities is known to be a composition of linear inequalities that can be found in the same variables.

The graph that is showing y > -3; y ≥ 2/3x - 4

-2 > -3 is true

y ≥ 2/3x - 4

-2 ≥ -2 is true

Therefore, y > -3; y ≥ 2/3x - 4 has the point (3, -2) in its solution set.

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