ZJSG09112007
contestada

A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.25m/s . Calculate :
a. How long is the ball in flight before striking the ground
b. How far from the building does the ball strike the ground

Respuesta :

msm555

Answer:

Solution given:

height [H]=25m

initial velocity [u]=8.25m/s

g=9.8m/s

now;

a. How long is the ball in flight before striking the ground?

Time of flight =?

Now

Time of flight=[tex]\sqrt{\frac{2H}{g}}[/tex]

substituting value

  • =[tex]\sqrt{\frac{2*25}{9.8}}[/tex]
  • =2.26seconds

the ball is in flight before striking the ground for 2.26seconds.

b. How far from the building does the ball strike the ground?

Horizontal range=?

we have

Horizontal range=u*[tex]\sqrt{\frac{2H}{g}}[/tex]

  • =8.25*2.26
  • =18.63m

The ball strikes 18.63m far from building.

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