Respuesta :

msm555

8x²y²z(2x-yz)

Answer:

Solution given;

16x³y²z-8x²y³z²

let look what is common there;

2*8*x²*x*y²*z-8*x²*y²*y*z*z

over here 8x²y²z is common

take common and keep other remaining on bracket

8x²y²z(2x-yz)

In a simple way 8x²y²z(2x-yz) is a factorise form of 16x³y²z-8x²y³z²