The rate constant for a particular second order reaction is 2.4 x 10-2 M-1 s-1 at 35∘C. If the initial concentration of the reactant is 1.20 M, what is the concentration (in M) after 4 minutes?

Respuesta :

Answer:

[tex]C_2=0.21M[/tex]

Explanation:

From the question we are told that:

Rate constant [tex]K=2.4 x*10^{-2} M-1 s-1[/tex]

Temperature [tex]T=35^o[/tex]

Initial concentration [tex]C_1=1.20M[/tex]

Time [tex]T=4min=>240sec[/tex]

Generally the equation for  second order reacion is mathematically given by

[tex]\frac{1}{C_2} = \frac{1}{C_1} +Kt[/tex]

[tex]\frac{1}{C_2} = \frac{1}{1.2 } +2.4 * 10^{-2} *240[/tex]

[tex]\frac{1}{C_2} = 4.8[/tex]

[tex]C_2=0.21M[/tex]