A pea plant that has round seeds has the genotype Rr. It crossed with a pea plant that has wrinkled seeds and the genotype rr. What is the probability that the offspring will have wrinkled seeds

1/2.
the gene Rr separate to R and r.
the gene rr separate to r and r.
then they mix, turn to
Rr, Rr, rr, rr.
because wrinkled gene r is recessive, so only rr would be wrinkled. the probability would be 2/4=1/2.

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samueladesida43 samueladesida43 · Answer 2 · 2020-04-18T03:30:36+02:00

Answer:

1/2 or 50%

Explanation:

This question involves a single gene coding for seed shape in pea plants. According to the question, the round allele (R) is dominant over the wrinkled allele (r) i.e. the round allele will mask the phenotypic expression of the wrinkled allele in a heterozygous state (Rr).

According to the question, a pea plant that is heterozygous for seed shape (Rr) is crossed with a homozygous recessive pea plant (rr). The cross will produce four possible offsprings with the genotypes: Rr and rr.

Rr genotype will be phenotypically round-seeded while rr will be phenotypically wrinkled.

Hence, the probability that an offspring with wrinkled seeds will be produced is 1/2 or 50%