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EGaddIndustries
I'll use the same notation as the other one:
3(y-6)<4(y+5)
I'm going to clean this up a bit by distributing:
3y-18<4y+20
Now, subtract 3y from both sides:
-18And now, subtract 20:
-38So y is greater than or equal to -38
Hope this helps!
SJ2006
3(y-6) ≤ 4(y+5)
3y-18 ≤ 4y+20

Subtract 3y from both sides,
3y-3y-18 ≤ 4y-3y+20
-18 ≤ y + 20

Subtract 20 from both sides,
-18-20 ≤ y+20-20
 -38 ≤ y

So, your final answer is y ≥ -38


Hope this helps!
 

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