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What is the equation of the following graph in vertex form?

parabolic function going down from the left and turning at the point negative one comma zero and going up through the point zero comma one and continuing towards infinity
Courtesy of Texas Instruments

y = (x − 1)2
y = (x − 1)2 + 1
y = (x + 1)2 − 1
y = (x + 1)2

What is the equation of the following graph in vertex form parabolic function going down from the left and turning at the point negative one comma zero and goin class=

Respuesta :

Correct answer is D.

Graph passes through the point (-1, 0).
Therefore, x = -1 and y = 0.

[tex]y=(x+1)^2 \\0=(-1+1)^2 \\0=0^2 \\0=0 \;\; \text{T}[/tex]

This is the only equation which is true for x = -1 and y = 0.
Therefore, the solution is [tex]y=(x+1)^2[/tex]

Answer:

y = (x + 1)^2

Step-by-step explanation:

I used desmos and put each answer choice into the graphing calculator and answer choice D was the only one that matched with the image in the question.

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