Answer: The order with respect to B is
Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]Rate=k[A]^x[B]^y[/tex]
k= rate constant
x = order with respect to A
y = order with respect to B
n = x+y = Total order
a) From trial 1: [tex]20=k[0.20]^x[0.10]^y[/tex] (1)
From trial 2: [tex]40=k[0.20]^x[0.20]^y[/tex] (2)
Dividing 2 by 1 :[tex]\frac{40}{20}=\frac{k[0.20]^x[0.20]^y}{k[0.20]^x[0.10]^y}[/tex]
[tex]2=2^y,2^1=2^y[/tex] therefore y=1.
Thus order with respect to B is 1.
