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The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same age have mean height 69.3 inches with standard deviation 2.8 inches. What are the z-scores for a woman 6 feet tall and a man 6 feet tall

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Answer:

z=(x-mu)/o

Step-by-step explanation:

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

b) Y = 72"

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

e) X>73"

Z>

Almost 0% can be taken

f) IQR =Q3-Q1