Answer:
[tex]secA = \frac{65}{63}[/tex]
Step-by-step explanation:
[tex]cosec A = \frac{65}{16}\\\\sin A = \frac{1}{cosecA} = \frac{16}{65}\\\\cos^2 A = 1 - sin^2 A[/tex]
[tex]= 1 - (\frac{16}{65})^2\\\\=\frac{4225-256}{4225}\\\\=\frac{3969}{4225}\\[/tex]
[tex]cos A = \sqrt{\frac{3696}{4225}} = \frac{63}{65}[/tex]
[tex]secA = \frac{1}{cosA} = \frac{65}{63}[/tex]
