Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
