Answer:
The distance between B to B' is 5
Step-by-step explanation:
Using the distance lie formula:
Let's say (x2, y2) is (-2,1) and (x1, y1) is (1,5)
[tex]\sqrt{(x2-x1)^{2} +(y2-y1)^{2} } \\\sqrt{(-2-1)^{2} +(1-5)^{2} } \\\sqrt{(-3)^{2} +(-4)^{2} } \\\sqrt{9+16}\\\sqrt{25} \\= 5[/tex]
The distance between the original and new coordinates would be the same, therefore the two will remain a distance of 5.
