Answer:
Step-by-step explanation:
[tex]h(t)=-16t^2+v_0t+h_0[/tex] where
h(t) is the height of the ball after a certain amount of time has gone by,
-16t² is the pull of gravity in ft/s/s,
v₀t is the initial upwards velocity, and
h₀ is the height from which the ball was initially thrown. Our equation is then, filling in the info in the correct places:
[tex]h(t)=-16t^2+128t+4[/tex] where 128 is the given initial velocity and 4 is the number of feet from which the ball was initially launched.
