Given:
Consider the below figure attached with this equation.
Quadrilateral QRST is a parallelogram.
To find:
The value of x.
Solution:
We know that the sum of two consecutive interior angles of a parallelogram is 180 degrees because they are supplementary angles.
In parallelogram QRST,
[tex]m\angle Q+m\angle T=180^\circ[/tex]
[tex](3x+5)^\circ+(9x-17)^\circ=180^\circ[/tex]
[tex](12x-12)^\circ=180^\circ[/tex]
On comparing both sides, we get
[tex]12x-12=180[/tex]
[tex]12x=180+12[/tex]
[tex]12x=192[/tex]
Divide both sides by 12.
[tex]x=\dfrac{192}{12}[/tex]
[tex]x=16[/tex]
Therefore, the value of x is 16.
