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If repetition of digits is allowed, how many different ways 5-digit codes are possible with the condition that the first digit should be a multiple of 3 and the last digit cannot be zero.
a. 17496.
b. 27000.
c. 18000.
d. 30000.

Respuesta :

clarch19

Answer:

b) 27,000

Step-by-step explanation:

3 × 10 × 10 × 10 × 9 = 27000

'3' because the first digit can only be 3,6, or 9

'9' because the last digit cannot be zero, leaving only 9 options

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