Answer:
The correct answer is:
(a) 44.6 lb
(b) 0.371
Step-by-step explanation:
Given values are:
Mean,
[tex]\mu=36.6[/tex]
Standard deviation,
[tex]\sigma=11.9[/tex]
(a)
The z distance third quartile will be:
⇒ [tex]P(Z<0.674)=0.75[/tex]
[tex]z =0.674[/tex]
By using the z-score formula, we get
⇒ [tex]x=z\times \sigma+ \mu[/tex]
[tex]=0.674\times 11.9+36.6[/tex]
[tex]=44.62[/tex]
(b)
⇒ [tex]P(27.5<x<39.5) = P[{\frac{(27.5-36.6)}{11.9} <\frac{(x-\mu)}{\sigma} <\frac{(39.5-36.6)}{11.9} }][/tex]
[tex]=P(-0.76<z<0.24)[/tex]
[tex]=P(z<0.24)-P(z<-0.76)[/tex]
By using the z table, we get
[tex]=0.5948-0.2236[/tex]
[tex]=0.371[/tex]