We are given the equation below:
[tex] \large{ {p}^{2} = \frac{9}{36} }[/tex]
Use the property below:
[tex] \large \boxed{ {x}^{2} = \frac{a}{b} \longrightarrow x = \pm \frac{ \sqrt{a} }{ \sqrt{b} } \: \: (a \geqslant 0 \: \: and \: \: b > 0)}[/tex]
From the equation:
[tex] \large{p = \pm \frac{ \sqrt{9} }{ \sqrt{36} } } \\ \large{p = \pm \frac{3}{6} \longrightarrow p = \pm \frac{1}{2} }[/tex]
Hence the answer is p = ± 1/2.
Answer
Both answers work. The second answer is in the plus-minus form.
Hope this helps! Let me know if you have any doubts.
