Answer:
√ [tex]\frac{3}{5} m[/tex]
Explanation:
Hope it helps!.
The change in the length of the spring will be 3.5 cm.Principal of the law of conservation of the momentum is applied in the problem.
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
Speed after impact is;
[tex]\rm v = \frac{(1.50)(3.5)}{(1.50)+(3)} \\\\ v= 1.1666 \ m/sec[/tex]
From the law of conservation of energy:
[tex]\rm \frac{1}{2} kx^2= \frac{1}{2} (m+M)v^2 \\\\ x= \sqrt{\frac{M+m}{k} } \\\\ x=\sqrt{\frac{4.5}{5000 } }(1.1666)\\\\ x= 0.35 \ m \\\\ x=3.5 \ cm[/tex]
The change in the length of the spring will be 3.5 cm.
To learn more about the law of conservation of momentum refer;
https://brainly.com/question/1113396
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