Rhombus JKLM is shown below. Find m∠KLM.
A.36°degree
B.38°degree
C,72°degree
D.76°degree

Answer:
Option D
Step-by-step explanation:
Properties of a rhombus,
1). Diagonals of a rhombus bisect the opposite angles.
2). Sum of adjacent two angles of a rhombus is 180°.
By property (1),
Diagonal JL will bisect the angles ∠MJK and ∠KLM.
Therefore, m∠KLM = 2(5x + 3)°
Similarly, diagonal KM will bisect the angles ∠JKL and JML.
Therefore, m∠JKL = 2(9x - 11)°
By property (2),
2(9x - 11)° + 2(5x + 3)° = 180°
9x - 11 + 5x + 3 = 90
14x - 8 = 90
14x = 98
x = 7
Since, m∠KLM = 2(5x + 3)°
= 2(5×7 + 3)°
= 76°
Therefore, Option D will be the answer.