The concentration of the sulfuric acid in the solution is 0.55m
Molarity is the measure of the concentration of any solute in per unit volume of the solution.
The reaction is
[tex]\rm NaOH+ 2H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O[/tex]
[tex]\rm M = \dfrac{n}{V}[/tex]
Moles = molarity × volume
0.236 M × 43.2 = 10.19 mol
The number of moles of sodium hydroxide = 10.19 mol
The ratio is 1:2
Then the moles of sulfuric acid is 10.19 × 2 =
Now, the molarity (concentration) of sulfuric acid is
[tex]\rm M = \dfrac{20.39}{36.7} = 0.55 m[/tex]
Thus, the concentration of the sulfuric acid is 0.55m.
Learn more about molarity, here:
https://brainly.com/question/12990095
