Respuesta :

Answer:

[tex]w = \sqrt{x} y[/tex]

Step-by-step explanation:

Formula used :

[tex]a \ log\ b = log \ b^a\\\\log a + log b = log \ ab[/tex]

 

[tex]log\ w = \frac{1}{2} log\ x + log \ y\\\\log \ w = log \sqrt{x} + log \ y\\\\log \ w = log \sqrt{x} y\\\\w = \sqrt{x} y[/tex]

That’s my answer ! I hope it help
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