Respuesta :
Answer:
[tex]w = \sqrt{x} y[/tex]
Step-by-step explanation:
Formula used :
[tex]a \ log\ b = log \ b^a\\\\log a + log b = log \ ab[/tex]
[tex]log\ w = \frac{1}{2} log\ x + log \ y\\\\log \ w = log \sqrt{x} + log \ y\\\\log \ w = log \sqrt{x} y\\\\w = \sqrt{x} y[/tex]