In Unit Circle, we know that x-term = cos and y-term = sin
[tex] \large \boxed{(x,y) = (cos \theta , sin \theta)}[/tex]
Recall the cotangent ratio:
[tex] \large \boxed{cot \theta = \frac{cos \theta}{sin \theta} }[/tex]
Because cotangent is reciprocal of tangent which is sin/tan so cotangent is 1/(sin/cos) = cos/sin.
Substitute the point in.
[tex] \large{cot \theta = \frac{ - 5}{ - 12 } \longrightarrow \frac{5}{12} }[/tex]
Answer
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