In the given figure p ∥ q , and t is a transversal then find the measures of a, b, c, d and e.
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Answer:
d=125-degree since p and q are parallel
b=d=125-degree since b and d are vertically opposite angles
a+d= 180-degree since they lie in straight line
Hence, a=180-125=55-degree
c=a=55-degree since a and c are vertically opposite angle
f=a=55-degree since a and f are alternate angle
e=f=55-degree since e and f are vertically opposite angle