Respuesta :

spectrojamz

Answer:

Let x be one of the numbers

then since they differ by 3... Let (x-3) be the 2nd Number

Their product is 88

(x-3)x = 88

x²-3x =88

x² - 3x - 88=0

Solving The quadratic eqn

x=11 or x = -8.

To check this answer

since the Numbers are x and x-3

x= 11

x-3 = 11 - 3 = 8

(x-3)x = 8x11 = 88.

Or When x=-8

(x-3) = -8 - 3 = -11

x= -8

(x-3)x = -8 x - 11 = 88.

Have a great day!

Answer:

First Set: [11, 8], Second Set: [-8, -11]

Step-by-step explanation:

The first number will be x. The second number is x-3. So now make an equation: x(x-3)=88 because their product equals 88. So now solve.

Solving:

[tex](x)(x-3)=88[/tex]

[tex]x^{2}-3x-88=0[/tex]

Now you can factor:

[tex](x-11)(x+8)=0[/tex]

[tex]x=11, x=-8[/tex]

Now plug in each number for x for the following equation:

[tex](x)(x-3)=88[/tex]

[tex](11)(11-3)=88[/tex]

[tex]88=88[/tex]

This is true.

[tex](-8)(-8-3)=88[/tex]

[tex]88=88[/tex]

This is true.

Both are true. So now you have two sets of answers.

Your welcome!

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