Answer:
A
Step-by-step explanation:
For this question, you want to use y=mx+c, where m is the gradient and c is the y-intercept.
We can see the line passes through (-4, 6) and (-1,2), so we can use those points to work out the gradient.
The formula for gradient is m=[tex]\frac{y_{2} -y_{1}}{x_{2}-x_{1}}[/tex]. By substituting the values above, you get m=[tex]\frac{6-2}{-4--1}[/tex], which becomes [tex]\frac{4}{-3}[/tex] or [tex]-\frac{4}{3}[/tex].
Since we can't exactly determine the y-intercept from the photo, we can sub it in to what we already know to work it out.
Using the point (-4, 6), y=[tex]-\frac{4}{3}[/tex]x+c can be written as 6=[tex]-\frac{4}{3}[/tex](-4)+c.
This can be expanded to 6=[tex]\frac{16}{3}[/tex]+c or 6=[tex]5\frac{1}{3}[/tex]+c.
Subtracting [tex]-\frac{4}{3}[/tex] from both sides gives c=[tex]\frac{2}{3}[/tex].
Putting this all back in the question, we get y= [tex]-\frac{4}{3}[/tex]x+[tex]-\frac{4}{3}[/tex], or A.
**This question involves writing linear equations, which you may want to revise. I'm always happy to help!
