Answer: The concentration of given solution is 11.68 M.
Explanation:
Given: Mass of solute = 10 g
Volume of solution = 25 mL
Convert mL into L as follows.
[tex]1 mL = 0.001 L\\25 mL = 25 mL \times \frac{0.001}{1 mL}\\= 0.025 L[/tex]
Number of moles is the mass of substance divided by its molar mass. The moles of sugar (molar mass = 342.3 g/mol) is as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{10 g}{342.3 g/mol}\\= 0.0292 mol[/tex]
Molarity is the number of moles of solute present in a liter of solution.
Hence, concentration of given solution is calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.0292 mol}{0.025 L}\\= 11.68 M[/tex]
Thus, we can conclude that the concentration of given solution is 11.68 M.
