I need help on this angles on a straight line problem, it involves algebra. I don't need an explanation just the answer please.
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Answer:
m<COD = 46°
Step-by-step explanation:
All the angles are supplementary to each other, so we can combine them and set them equal to 180° to solve for x:
(3x+88)°+(x+36)°+(2x-4)°=180°
3x+88+x+36+2x-4=180
6x+120=180
6x=60
x=10
Since we know x=10, then <COD is 10+36 = 46°
Answer:
∠COD = 46°
Step-by-step explanation:
∠AOB (or straight line) = 180°
3x + 88° + x + 36° + 2x - 4° = 180°
combine like terms:
6x + 120° = 180°
subtract 120° from both sides of the equation:
6x = 60°
divide both sides by 6:
x = 10°
∠COD = 10° + 36° = 46°