Answer: Concentration of the acid is 0.551 M.
Explanation:
Given: [tex]V_{1}[/tex] = 71.1 mL, [tex]M_{1}[/tex] = 0.695 M
[tex]V_{2}[/tex] = 89.7 mL, [tex]M_{2}[/tex] = ?
Formula used to calculate the concentration of acid is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.695 \times 71.1 mL = M_{2} \times 89.7 mL\\M_{2} = 0.551 M[/tex]
Thus, we can conclude that concentration of the acid is 0.551 M.
