Uranium-235 decays to thorium-231 with a half-life of 700 million years. When a rock was formed, it contained 6400 million uranium-235 nuclei and no thorium-231 nuclei. Show that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.

Respuesta :

Answer:

proof in explanation

Explanation:

First, we will calculate the number of half-lives:

[tex]n = \frac{t}{t_{1/2}}[/tex]

where,

n = no. of half-lives = ?

t = total time passed = 2100 million years

[tex]t_{1/2}[/tex] = half-life = 700 million years

Therefore,

[tex]n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3[/tex]

Now, we will calculate the number of uranium nuclei left ([tex]n_u[/tex]):

[tex]n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u = 800\ million[/tex]

and the rest of the uranium nuclei will become thorium nuclei ([tex]u_{th}[/tex])

[tex]n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million[/tex]

dividing both:

[tex]\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u[/tex]

Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.