Respuesta :
Answer:
.0016
Explanation:
For specific heat problems you use the formula :
Q = mcΔT
They've given you the m, c and delta T, so you can plug in those values. (for the temperature change subtract 10 from 40 to see that it grew 30 degrees)
You're looking for Q so leave that variable in the equation. Then solve.
.Q = (8.00)(.384)(30)
Q = 92.16
92.16 J energy will be absorbed by a copper sample.
Given:
Specific heat capacity, C= 0.384 J/g °C
Temperature, T₁ = 10.0°C and T₂= 40.0°C
Mass, m=8.00 g
We know that,
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (g) of the material when its temperature increases or 1 °C, and its unit is J/g °C.
Heat energy in terms of specific heat energy can be calculated by using this formula:
Q= m. C. ΔT
∵ΔT= change in temperature,
ΔT=40.0-10.0°C=30°C
Now substituting the values in the above formula.
[tex]Q= 8.0*0.384*30=92.16J[/tex]
Hence, 92.16 J energy will be absorbed by a copper sample.
Learn more:
brainly.com/question/22991121
