Given:
The vertices of a triangle JKL are J(0, 2), K(–1, 2), and L(0, –3).
To find:
The coordinates of the image of point J after a dilation with a scale factor of 3.
Solution:
If a figure is dilated by a scale factor of k, then
[tex](x,y)\to (kx,ky)[/tex]
The given triangle JKL dilated by a scale factor of 3. So,
[tex](x,y)\to (3x,3y)[/tex]
The coordinates of point J are J(0,2). By using the above rule, we get
[tex]J(0,2)\to J'(3(0),3(2))[/tex]
[tex]J(0,2)\to J'(0,6)[/tex]
Therefore, the coordinates of the image of point J after a dilation with a scale factor of 3 are J'(0,6).
