How do I do this and show work
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We are given the expression:
[tex]\frac{\sqrt{2} }{3} = -\frac{2}{3} Sin\theta[/tex]
[tex]\sqrt{2}} = -2 Sin\theta[/tex] [multiplying both sides by 3]
[tex]Sin\theta = \frac{\sqrt{2}}{-2}[/tex] [Dividing both sides by -2]
[tex]Sin\theta = \frac{-1}{\sqrt{2}}[/tex]
which means:
[tex]\theta = Sin^{-1}(\frac{-1}{\sqrt{2}} )[/tex]
[tex]\theta = -Sin^{-1}(\frac{1}{\sqrt{2}} )[/tex]
θ = -45° [because [tex]Sin^{-1}(\frac{1}{\sqrt{2}})[/tex] = 45°]
Hence, the answer is -45° OR (360-45) = 315°