the straight line L passes through the points (0 , 12) and (10 , 4).

Find an equation of the straight line which is parallel to L and passes through the point (5 , -11).

Respuesta :

Answer:

y = - [tex]\frac{4}{5}[/tex] x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 12) and (x₂, y₂ ) = (10, 4)

m = [tex]\frac{4-12}{10-0}[/tex] = [tex]\frac{-8}{10}[/tex] = - [tex]\frac{4}{5}[/tex] ← slope of line L

Parallel lines have equal slopes , then

y = - [tex]\frac{4}{5}[/tex] x + c ← is the partial equation

To find c substitute (5, - 11) into the partial equation

- 11 = - 4 + c ⇒ c = - 11 + 4 = - 7

y = - [tex]\frac{4}{5}[/tex] x - 7 ← equation of parallel line