the probabilities that amy and tess will arrive at party on time are 2/3 and 3/4 respectively. Find the probability that a. amy will arrive on time while tess is not

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Answer:

1/6

Step-by-step explanation:

Probability that any arrives on time = 2/3

Probability that teaa arrives on time = 3/4

Probability that teas will not arrive in time = 1 - P(tess arrives on time) = 1 - 3/4 = 1/4

Hence,

The probability that Amy arrives in time and tess does not equals

2/3 * 1/4 = (2*1) / (3*4) = 2 / 12 = 1/6

Using it's concept, it is found that there is a 0.1667 = 16.67% probability that Amy will arrive on time while Tess will not.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem:

  • The probability that Amy arrives on time is of 2/3.
  • The probability that Tess does not arrive on time is of 1/4.

Since they are independent, we multiply them, hence:

[tex]P = \frac{2}{3} \times \frac{1}{4} = \frac{2}{12} = 0.1667[/tex]

0.1667 = 16.67% probability that Amy will arrive on time while Tess will not.

More can be learned about probabilities at https://brainly.com/question/14398287