Answer:
3.2
Explanation:
The missing graph is attached in the image below:
Initially, p.H from the graph is approximately 2.1
Therefore; the hydrogen ion concentration is
[tex][H^+] = 10^{-2.1}[/tex]
[tex][H^+] = ({k_a \times 0.10})^{\dfrac{1}{2}}[/tex]
[tex]{k_a} = 6.3 \times 10^{ -4}[/tex]
pKa = [tex]-log ( 6.3 \times 10^{-4})[/tex]
pKa = 3.2
